Question on Power Amplifier

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bigheadfish

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"If the power amplifier generates 1W, then an attenuation of 2dB in the filter translates to 370mW loss of power"

I think 10*log(0.37/1)=-4.3dB , not -2dB. Am I right?
 

Check out this:

Input power = 1W
Output power = 1W - 0.37W = 0.63W

10 x log (0.63/1) = -2dB

Regards,
IanP
 
Thanks! I have another question.

"if the TX power amplifier delivers 1W to a 50Ω antenna, the peak to peak voltage swing is equal to 20V. The leakage to the receiver path is on the order of 30mVpp(=-26dBm)"

I think P=Vpp*Vpp/(2*R), then Vpp=10V ,not 20V. Am I right?
30mVpp=-26dBm? How can I get it?
 

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