Re: Z Transform question
Fine...but see as the Laplace transform converts your time domain signal to the freq domain, just like that the Z-transform allows you to make complex domain analysis of your poles & zeros of your transfer function h
, where your index n is the nT{in time domain only}, while your index Z in H(z) will be complex. It means it maps your time domain to the complex domain...as per the best of my knowledge the Z-plain gives you the idea about stability on the basis of location/placement of poles n zeros. thats why z-transform deals with stability of the digital system.
And in some literature, u may find Z transform explained as impedance transform, bcoz basically your h
is h(nT)=output/input, which directly means the ratio of Vout/Vin for any network.........!!!
---------- Post added at 05:17 ---------- Previous post was at 05:16 ----------
Fine...but see as the Laplace transform converts your time domain signal to the freq domain, just like that the Z-transform allows you to make complex domain analysis of your poles & zeros of your transfer function h
, where your index n is the nT{in time domain only}, while your index Z in H(z) will be complex. It means it maps your time domain to the complex domain...as per the best of my knowledge the Z-plain gives you the idea about stability on the basis of location/placement of poles n zeros. thats why z-transform deals with stability of the digital system.
And in some literature, u may find Z transform explained as impedance transform, bcoz basically your h
is h(nT)=output/input, which directly means the ratio of Vout/Vin for any network.........!!!