Maybe this one is a little clearer.
Hi obrien135,
When making the loop gain you are forgetting the effect of first capacitor of the pi-network (let's say
C1), which is charging the ouput of the amplifier section (at transistor collector).
Possibilities to solve this:
1) Use C1 as part of load of your amplifier, in parallel with Rc --> you will get a complex gain for the amplifier section and a complex number at the gain loop --> then you force the imaginary part to 0 to get the oscillation condition (the frequency for which the phase shift is 0)
2) Use the Thevening equivalent for your amplifier output and then complete it with the feeback network (pi-network) --> Thevening schematic are usually more friendly to use (may be it is just a matter of visual).
Don't be afraid to repeat the Thevening but this time with C1, which will lead again to a complex Vthevening (Vth). The Rth will also be complex. --> Now you have all impendances and resistances in series with Vth, which allows you to easily calculate the voltage transfer.
At the end you shoul reach the following oscillation condition: Ao > C2/C1, where Ao=Rc/re
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This conceptual problem is coming from the theory where it is said that for getting oscillations, (Ao)B>1 where Ao is the amplifier gain in open loop. But even in open loop, you have to considere the possible charges that could be attached to the output (C1 in this case). the same thing sould be said for the end the feedback where to mathematically more near of reality, the Beta*re resistance should have been shown just in parallel with C2. This has not been done and it is justified as far as we can demonstrate that Beta*re >> X2 (=1/wC2) at the osciallation frequence, which is usually the case in common-emmitter configurations (you can check this - take the challenge)
Note that you can not remove C1 because in that case there will not be a 180 phase shift and oscillations will never occur.
Hope it helped a little bit.