But in this circuit the no load current is in order of KA. Is this current something other than Magnetizing current?
Neglecting those 10 mA, those kA are
exactly the magnetizing current.
How we can know what is the value of Xm in XFRM_linear? Is it the 10uH value?
Yes, Lm = 10 uH in your case.
You are the one to set the magnetizing inductance of the transformer. It can be 10 uH or any value you want... double click the XFRM_linear part (or open its properties) and set its inductance values on L1 and L2. Remember N1/N2=√(L1/L2).
Depending on what side of the transformer you are looking from, with other words, you are taking as input i.e. setting the input voltage source to that side, the magnetizing inductance will be
exactly the inductance of that side.
For example, if you are taking the primary as input, then L1=L
magnetizing inductance and hence V
in/X
L will be the magnetizing current (neglecting any other voltage drop on that mili ohm resistor you set in series with the ideal voltage source).
If you are seeing it from the other side i.e. placing the input source to the secondary side, L2=L
magnetizing inductance ... no one cares from which side a transformer is seen...