Dec 13, 2014 #1 K kenambo Full Member level 6 Joined Feb 26, 2012 Messages 393 Helped 52 Reputation 104 Reaction score 48 Trophy points 1,308 Location India Activity points 3,859 Hi all what will happen my forward applied bias voltage reaches or exceeds the built-in potential.. Is it possible to entirely vanish the depletion region in a diode? according to equation barrier voltage = q(Vbi-Vapplied) if vbi=Vapplied barrier = 0V am i right?
Hi all what will happen my forward applied bias voltage reaches or exceeds the built-in potential.. Is it possible to entirely vanish the depletion region in a diode? according to equation barrier voltage = q(Vbi-Vapplied) if vbi=Vapplied barrier = 0V am i right?
Dec 13, 2014 #2 D dick_freebird Advanced Member level 7 Joined Mar 4, 2008 Messages 8,960 Helped 2,333 Reputation 4,683 Reaction score 2,514 Trophy points 1,393 Location USA Activity points 71,402 Yes, once you inject forward current there is no depletion anymore. There are carriers moving through where it used to be.
Yes, once you inject forward current there is no depletion anymore. There are carriers moving through where it used to be.
Dec 14, 2014 #3 D.A.(Tony)Stewart Advanced Member level 7 Joined Sep 26, 2007 Messages 9,007 Helped 1,823 Reputation 3,645 Reaction score 2,199 Trophy points 1,413 Location Richmond Hill, ON, Canada Activity points 59,560 kenambo said: Hi all what will happen my forward applied bias voltage reaches or exceeds the built-in potential.. Is it possible to entirely vanish the depletion region in a diode? according to equation barrier voltage = q(Vbi-Vapplied) if vbi=Vapplied barrier = 0V am i right? Click to expand... Vbi = Vt*ln(Na*Nd/ni²)= = Built-in Potential Barrier .... Vbi≠0 Va = Applied forward bias voltage
kenambo said: Hi all what will happen my forward applied bias voltage reaches or exceeds the built-in potential.. Is it possible to entirely vanish the depletion region in a diode? according to equation barrier voltage = q(Vbi-Vapplied) if vbi=Vapplied barrier = 0V am i right? Click to expand... Vbi = Vt*ln(Na*Nd/ni²)= = Built-in Potential Barrier .... Vbi≠0 Va = Applied forward bias voltage
Dec 15, 2014 #4 K kenambo Full Member level 6 Joined Feb 26, 2012 Messages 393 Helped 52 Reputation 104 Reaction score 48 Trophy points 1,308 Location India Activity points 3,859 So the immobile charge carriers of p-side and n-side got their respective holes and electrons when we apply a sufficient forward voltage. is it correct?
So the immobile charge carriers of p-side and n-side got their respective holes and electrons when we apply a sufficient forward voltage. is it correct?