Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Pls help to explain this 3ph symmetrical fault problem...

Status
Not open for further replies.

powersys

Advanced Member level 1
Joined
Nov 29, 2005
Messages
440
Helped
3
Reputation
6
Reaction score
2
Trophy points
1,298
Activity points
4,987
The Example 9-1 shown in the attached images was taken from Power System Analysis (2ed, by Hadi Saadat). I do not understand the part marked by the red outline rectangle:

ΔV1 = 0.00 - (j0.20)(-j1.20) = -0.24 pu
ΔV2 = 0.00 - (j0.40)(-j0.80) = -0.32 pu
ΔV3 = (j0.16)(-j2.00) - 1.00 = -0.68 pu

Why "0.00" was used to calculate the ΔV1 and ΔV2? How do the equations above come about? Pls advise.

Thanks.

HSEX9-1PART-A-EDITED.jpg

HSEX9-1PART-B-EDITED.jpg
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Top