syedshan
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hi all,
please see the following snippet.
I want to know what it actually does, does it mean the following
1. INST will call the respective internal clock signals and then connect them to BUFGCTRL, but what will it achieve. Also why the Slice dimensions are necessary here?
thanks
please see the following snippet.
Code:
#INST "*/i_clkrst_*/bufg_slow_capt" LOC = BUFGCTRL_X0Y26;
INST "*/i_clkrst_*/i_ddr_pll/clkout5_buf" LOC = BUFGCTRL_X0Y27;
INST "*/i_clkrst_*/bufg_fast_capt" LOC = BUFGCTRL_X0Y28;
INST "*/i_clkrst_*/i_ddr_pll/clkout1_buf" LOC = BUFGCTRL_X0Y29;
INST "*/i_clkrst_*/clk_200_inst/clkout1_buf" LOC = BUFGCTRL_X0Y4;
INST "*/i_clkrst_*/bufg_capt_reset" LOC = BUFGCTRL_X0Y5;
INST "*/i_clkrst_*/i_ddr_pll/mmcm_adv_inst" LOC = MMCM_ADV_X0Y11;
I want to know what it actually does, does it mean the following
1. INST will call the respective internal clock signals and then connect them to BUFGCTRL, but what will it achieve. Also why the Slice dimensions are necessary here?
thanks