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opamp psrr measurement

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pianomania

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about the OPamp psrr measurement , should we test it in
1 openloop like connect the two input , then measure the output variation

or

2 close loop : like connect the op as the Opamp buffer then measure the output variation?

the two kind of testing have very different result.
which one is reasonale , why?
 

I believe the closed-loop is the correct one because Open-loop opamps have practically 0dB PSRR.
 

I think the first open loop is like a dc psrr,the second is ac psrr
 

Both open-loop and closed-loop approaches are possible ("open loop" means closed-loop with large RC in the feedback, not "true open loop" configuration).

Open loop simulation is described in Backer/Li/Boyce "CMOS Circuit Design, Layout, and Simulation" (1st ed., p. 633).

Closed-loop simulation is described in Allens/Holberg "CMOS Analog Circuit Design" (2nd ed., p. 432).

In the attached figure results of both simulations are shown for comparison. A considerable difference is observed after cut-off frequency, so in most cases either method can be used.

pianomania said:
the two kind of testing have very different result.

As you can see from attached figure results are very close, so likely you made some mistake.

fcfusion said:
... because Open-loop opamps have practically 0dB PSRR.

Didn't you mix up PSRR (Adm/Add) with (1/Add)?
 

I have typically used closed loop in past life. The open loop is too susceptible to "instability" etc. Maybe fine for sims but for testing ...
 

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