Feb 12, 2018 #1 J joric Newbie level 3 Joined Feb 12, 2018 Messages 3 Helped 0 Reputation 0 Reaction score 0 Trophy points 1 Activity points 30 The thermal noise power of a channel with a bandwidth of 400 kHz is 1.776 x 10–15 watts, what is its operating temperature in ℃? N = kTB N = thermal noise in watts k = Boltzmann’s constant = 1.38 x 10-23 T = Temperature in kelvin x + 273 T = N / kB N = 1.776 x 10^-15 k = 1.38 x 10^-23 B = 4 x 10^5 T = 1.776 x 10^-15 / 1.38 x 10^-23 * 4 x 10^5 = 1.776 x 10^-15 / 5.2 x 10^-18 = 0.341538461 x 10^3 = 341.538k 341.538 -273 = 68.538 ℃ Is the answer correct?
The thermal noise power of a channel with a bandwidth of 400 kHz is 1.776 x 10–15 watts, what is its operating temperature in ℃? N = kTB N = thermal noise in watts k = Boltzmann’s constant = 1.38 x 10-23 T = Temperature in kelvin x + 273 T = N / kB N = 1.776 x 10^-15 k = 1.38 x 10^-23 B = 4 x 10^5 T = 1.776 x 10^-15 / 1.38 x 10^-23 * 4 x 10^5 = 1.776 x 10^-15 / 5.2 x 10^-18 = 0.341538461 x 10^3 = 341.538k 341.538 -273 = 68.538 ℃ Is the answer correct?
Feb 12, 2018 #2 M mjuneja Advanced Member level 4 Joined Aug 28, 2016 Messages 105 Helped 12 Reputation 24 Reaction score 10 Trophy points 18 Location Bangalore, India Activity points 674 joric said: The thermal noise power of a channel with a bandwidth of 400 kHz is 1.776 x 10–15 watts, what is its operating temperature in ℃? N = kTB N = thermal noise in watts k = Boltzmann’s constant = 1.38 x 10-23 T = Temperature in kelvin x + 273 T = N / kB N = 1.776 x 10^-15 k = 1.38 x 10^-23 B = 4 x 10^5 T = 1.776 x 10^-15 / 1.38 x 10^-23 * 4 x 10^5 = 1.776 x 10^-15 / 5.2 x 10^-18 = 0.341538461 x 10^3 = 341.538k 341.538 -273 = 68.538 ℃ Is the answer correct? Click to expand... No There is a mistake in your calculation. T = 1.776 x 10^-15 / (1.38 x 10^-23 * 4 x 10^5) = 1.776 x 10^-15 / 5.52 x 10^-18 = 321.739 K.
joric said: The thermal noise power of a channel with a bandwidth of 400 kHz is 1.776 x 10–15 watts, what is its operating temperature in ℃? N = kTB N = thermal noise in watts k = Boltzmann’s constant = 1.38 x 10-23 T = Temperature in kelvin x + 273 T = N / kB N = 1.776 x 10^-15 k = 1.38 x 10^-23 B = 4 x 10^5 T = 1.776 x 10^-15 / 1.38 x 10^-23 * 4 x 10^5 = 1.776 x 10^-15 / 5.2 x 10^-18 = 0.341538461 x 10^3 = 341.538k 341.538 -273 = 68.538 ℃ Is the answer correct? Click to expand... No There is a mistake in your calculation. T = 1.776 x 10^-15 / (1.38 x 10^-23 * 4 x 10^5) = 1.776 x 10^-15 / 5.52 x 10^-18 = 321.739 K.