divide by 3 counter design
khaila said:
The solution seems to be a tricky one.
May you explain what N is considered to???
What do you mean by ENABLED AT??? so you mean initialed with 0 or 1???
Hi .
N => Mod of ur Counter
ex. For divide by 3 take N=3.
Enabled means Enabling of F/F .
so you mean initialed with 0 or 1??? =>ya initialied with '1'...
Any other comment ????
Regards[/quote]
Thanx for the response but I still not satisfied with your explanations.
If I will substitute N=3 then the result as your equation is: 4
So what I can do with this value when you ask to enabled at 4!!!
It still not clear to me.
Please, Please, Please explain more.
It will be great if may discussed an example.[/quote]
Hi
Sorry For my mistake it is [(n-1)/2]+1.
take Exp. for divide by 3 with 50 % duty cycle ..
so make circuit for Mod 3 counter (synchronous)...
so state of this counter is 0 ,1 & 2.
so now +ve edge F/F enabled it at 0
-ve edge triggered F/F enabled it at [(3-1)/2]+1 = 2
so now take o/p of both FF and give to input of exor gate ...
at o/p of exor gate you will get "Divide by3 with 50% duty cycle "..
Regards
Added after 1 minutes:
Hi
any other comments ?? Welcome..
Regards