Oct 25, 2010 #1 BAT_MAN Member level 5 Joined Oct 9, 2006 Messages 90 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,286 Activity points 1,845 I am confused in calculating inverse in finite field Gf( 2^8 ) using extended euclidean method of (x6+x4+x+1)^-1mod (mod x8+x4+x3+x+1)
I am confused in calculating inverse in finite field Gf( 2^8 ) using extended euclidean method of (x6+x4+x+1)^-1mod (mod x8+x4+x3+x+1)