ssudhasa
Newbie level 6
Hi, I have a question.
CLKA = 2 × CLKB
Signal in CLKA domain is active for 2 CLKA cycle.
At clock domain crossing we have used 2 bit synthronizer,
At synthronizer output, how many CLKB cycles it will have . ??
options:
(1) 1
(2) 2
(3) 3
And Also , for this MCD scenario, 2 bit synthronizer is sufficient?
Thanks in Anticipation!!
CLKA = 2 × CLKB
Signal in CLKA domain is active for 2 CLKA cycle.
At clock domain crossing we have used 2 bit synthronizer,
At synthronizer output, how many CLKB cycles it will have . ??
options:
(1) 1
(2) 2
(3) 3
And Also , for this MCD scenario, 2 bit synthronizer is sufficient?
Thanks in Anticipation!!