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8051 has weak pull-up resistors, you need to write 0 to the ports to pull the pins to 0, involving 50 µA current per pin. For minimum sleep current, you would switch the display GND pin and VEE circuit instead of VDD and leave port 1 floating.i have found that the signal lines(port 1) of lcd are still powered up even if i off the lcd and have also high the pins of lcd at the time when lcd is off.... and also power pins of LCD shows me 1.32v....
can anybody plzz help me.... how to make the pins to 0v
Will still keep an unwanted large L293 quiescent current. Review the datasheet. The part is simply not well suited for battery operation.Try grounding EN2, IN3 & IN4 of L293
Any battery operated instrument design needs a calculation of battery liftetime, considering current in operation, duty cycle, idle current. I don't know what "for long" means for you.but will it sustain for long...
sbit dc3=P3^3; //IRF630N
sbit dc4=P3^4; //IRF630N
sbit dc5=P3^5; //IRF9540N
sbit dc6=P3^6; //IRF9540N
dc3=0;dc5=1;
dc6=1;dc4=0;
dc3=1;dc5=0;
{
msdelay(700);
dc3=0;dc5=1;
}
dc6=0;dc4=1;
{
msdelay(700);
dc6=1;dc4=0;
}
sbit dc3=P3^3; //IRF630N
sbit dc4=P3^4; //IRF630N
sbit dc5=P3^5; //IRF9540N
sbit dc6=P3^6; //IRF9540N
P3^4 irf630n MOSFET drain pin connected to ground....
sorry not shown in circuit diagram
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