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microstrip resonator simulation question

yefj

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Hello, a resonator which is an open circuit stripline was built as shown bellow exactly as described in the example bellow.
Smith chart and S-params and E-field are as shown bellow.
I am used to think that at resonance our S-params is supposed to very low.
Where did i go wrong?
Maybe resonance and being impedance matched is no the same thing?
Thanks.
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yefj

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Hello FVM,Shown bellow real and imag of S11,what should i see in here that says there is resosnance?
why its acting accordingly.

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yefj

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Hello FVM, Why Z11 peaks at resonance according to this expression?
Why Z11 is Zin?
Thanks.

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yefj

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UPDATE: i see that at 4.866GHZ my input impedance is purely resistive.
How do i also make it perfectly matched?
I need to lower the width of the strip line?

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yefj

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Hello, FVM as you can see my resonator no matter what line width my input impedance .
for L=25mm we have resonance at f=4.33GHz
i am trying to see why my input impedance is getting purley resistive at f=4.33GHz.
I have an expression as shown bellow.
What is my L and C for my open circuit microstrip.
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BigBoss

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-Parallel Resonance Circuit exhibits OPEN Circuit @ resonance as you have in your simulation charts.
-\[ Z_{in}=Z_{11} \] Because you have only ONE Port
-The resonance Frequency of the resonator is esentially defined by the Length, NOT much by Width ( interpret hyperbolic function in the equation )

You got a resonator that works @ Peak Frequency of \[ Z_{11} \]. What else you wanna see ?
 

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