Maximum weight this servo motor can handle?

I am using a Pan and tilt mechanism with a mini-servo motor(see image) for my project.



The perpendicular distance from the shaft of the servo to the top base of the pan and tilt mechanism is 3cm. The torque of the servo motor is 1.8Kgcm for 4.8V.

Since, Torque = Force * Distance,
Force = Torque/Distance,
Force = 1.8/3 = 0.6 Kg

Does this mean I can have a maximum weight of 600g on the top base? Does the weight that can be loaded depend on only the perpendicular distance from the shaft to the base, and not on the length and breadth of the top base?

Am I correct in this calculation, or way off?

The entire dimensions of the pan and tilt mechanism are:


The further specifications of my mini-servo motor are
Required Pulse: 3-5 Volt Peak to Peak Square Wave
Operating Voltage: 4.8-6.0 Volts
Operating Temperature Range: -10 to +60 Degree C
Operating Speed (4.8V): 0.12sec/60 degrees at no load
Operating Speed (6.0V): 0.10sec/60 degrees at no load
Stall Torque (4.8V): 1.8kg/cm
Stall Torque (6.0V): 2.4kg/cm
360 Modifiable: Yes
Bearing Type: Ball Bearing
Gear Type: Nylon Gears
Connector Wire Length: 12"
Dimensions: 22x11.5x27mm
Weight: 11g

Thanks,
Karthik

This picture show, how to calculate torque in this tilt mechanism.



If r= 6cm , then force is (1.8kpcm) / (6cm) = 0.3kp

but if angle is 45° then
l=6cm*cos(45°) = 4.24cm
and force is (1.8kpcm) / (4.24cm) = 0.425kp

angle is 60° then force is 0.6kp

etc....

add torque of friction forces to this rotational torque

KAK

Looking to the picture, it is a normal gear mechanism (not worm gear). This means when you have a static load, there will run constant current through the motor under zero RPM condition. This may lead to excessive temperature rise.

What type of motor do you have (DC with brushes or brushless, Stepper motor, etc)? You mention "stall torque" this may indicate that in a practical situation you need to stay well below this.