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Logic level shift of DC Square wave from Hall Effect Sensor

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Hi,

I m currently using a Hall Effect Sensor from Allegro (A1212).
It is attached in the DC motor assembly, and the sensor output goes from 8V to 13.5 square wave pattern for each rotation of the motor shaft.

I need to bring it down to 0-5 V logic level to make my controller understand.

There were some circuits that are given as reference but I m totally confused, on how it works.

As per the reference material I have , the I/p is Raw signal from the Hall Effect Sensor, and O/p is the Conditioned Sensor Output.

Any help regarding this would be much helpful.

Thanks,
Deepan
 

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Hi,

what do you expect us to do?

Verify the circuit? .. without values.

Mind: we don´t have informations about VBatt nor do we have any timing informations.

Klaus

Added:
The allegro A1212 sensor has an open drain output and thus should draw the voltage down to zero volts.
Thus I´m confused how the signal voltage information fits to the A1212 sensor.
 

If for some strange reason the voltages are as you stated, if you drop them through a series 8.2V Zener diode and resistor to ground, the voltage at their junction will be (13.5 - 8.2) = 5.3V and (8 - 8.2) = effectively zero. Is that close enough?

Brian.
 
Hi,

I m currently using a Hall Effect Sensor from Allegro (A1212).
It is attached in the DC motor assembly, and the sensor output goes from 8V to 13.5 square wave pattern for each rotation of the motor shaft.

I need to bring it down to 0-5 V logic level to make my controller understand.

There were some circuits that are given as reference but I m totally confused, on how it works.

As per the reference material I have , the I/p is Raw signal from the Hall Effect Sensor, and O/p is the Conditioned Sensor Output.

Any help regarding this would be much helpful.

Thanks,
Deepan

Hi,
Below circuit may work. I used ISO1211 for a similar purpose.
 

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Hi,

what do you expect us to do?

Verify the circuit? .. without values.

Mind: we don´t have informations about VBatt nor do we have any timing informations.

Klaus

Added:
The allegro A1212 sensor has an open drain output and thus should draw the voltage down to zero volts.
Thus I´m confused how the signal voltage information fits to the A1212 sensor.


Neither do I have the values for the circuit, it has been given just for the name sake..... I persume that it has nothing to do with the requirement I have,

If i try to put it straight, I have a device , connected at the motor shaft which gives me pulse for every RPM, for which pulse peak is at 13.2VDc, and pulse lowside voltage is 8.0VDc, and they are equally split for the 180 of rotation of the shaft,

Hence now , I have a pulsating DC signal , that floats between 8.0 to 13.2 VDc, I need to get it to 0-5V range in the same frequency at which it is happening as that of the source, so that my MCU can understand

Hope I have explained a bit clear from my very first post in EDABOARD..
 

If for some strange reason the voltages are as you stated, if you drop them through a series 8.2V Zener diode and resistor to ground, the voltage at their junction will be (13.5 - 8.2) = 5.3V and (8 - 8.2) = effectively zero. Is that close enough?

Brian.
Looks promising... Let me try it out..
 

Hi,
Below circuit may work. I used ISO1211 for a similar purpose.
Looks like one such solution , I was expecting, but I m worrying about the BOM parts, and cost of it.
 

Hi,

still no timing no frequency....when you design such a circuit you need to have at least a raw estimation of the requirements...

My usual way is to use a comparator....


Klaus
 
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