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Is it possible to use attenuator instead of load ?

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MK28

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help

Hi all,

is it possible to use -30db attenuator instead of 50Ω load for terminating any port ?
how it works with attenuator...please explain...
 

Re: help

That's OK. Theoretically, with a perfect 30dB attenuator can obtain at least 60dB return loss, and that's enough.

A attenuator is a loss network to absorb given engry. There is many types of attenuator, which I'm familiar with is Pi or T -type resistor network. A lot of text book introduce this circuits.
 

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