Nov 20, 2007 #1 K keni4eva Newbie level 5 Joined Sep 30, 2007 Messages 10 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,345 Pls intergrate the attached questions using the REDUCTION FORMULAE
Nov 27, 2007 #2 MSRA Full Member level 2 Joined Nov 18, 2006 Messages 130 Helped 3 Reputation 6 Reaction score 0 Trophy points 1,296 Location NED Pakistan Activity points 2,207 i'm unable dowload it...y?
Dec 4, 2007 #3 K kvsm2k Newbie level 5 Joined Nov 27, 2007 Messages 10 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Location Trivandrum Activity points 1,345 Hi, what u send the integral equation if one of the theory. U can see in any intermediate maths book in that go to integration section, then u can easily get the proof of and other methods also.
Hi, what u send the integral equation if one of the theory. U can see in any intermediate maths book in that go to integration section, then u can easily get the proof of and other methods also.
Dec 12, 2007 #4 S SWINI Member level 3 Joined Mar 19, 2007 Messages 58 Helped 5 Reputation 10 Reaction score 3 Trophy points 1,288 Activity points 1,555 solution follows as: let I=∫eax cos bx dx I=(e ax cos bx/a) + ∫(b/a)(e ax) (sin bx) dx I=(e ax)(cos bx)/a + { (b/a(e ax)(sin bx))-b²/a²I} I=(e ax)(acos bx+b sin bx)/(a²+b²) have any more doubts in this solution plz kindly reply????
solution follows as: let I=∫eax cos bx dx I=(e ax cos bx/a) + ∫(b/a)(e ax) (sin bx) dx I=(e ax)(cos bx)/a + { (b/a(e ax)(sin bx))-b²/a²I} I=(e ax)(acos bx+b sin bx)/(a²+b²) have any more doubts in this solution plz kindly reply????
Jan 17, 2008 #5 P pankajrangaree1 Junior Member level 2 Joined Jan 8, 2008 Messages 24 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,368 1st integration of second minus integration of d/dx of 1st into integration of second.i think this is the reductionn formula
1st integration of second minus integration of d/dx of 1st into integration of second.i think this is the reductionn formula