Dear baby_1
Hi
At AC , capacitor will charge , too . it is the cause of it's impedance . it will charge at 1/4 of cycle and will discharge at 1/4 of cycle too . and ...... etc ( + and negative ) . so , the capacitor can't occupy more than supply voltage , unless it will be at a current source , thus it can accept higher charges .
Best Luck
Goldsmith
Infinite voltage ???!!! it is impossible ! but if you need a current source for very high voltages , you should try to create a high voltage ( nearby some kilo volts ) and then use it as supply of your current source . to achieve high power current source , there are many ways available , that depends on your purpose .
Best Wishes
Goldsmith
Yes,i know it is impossible to get infinite.but i want to create a circuit that charge capacitor with current source by time.if i do it with an CE current source it doen't work.now how can i should create current source for low voltage (10 Volt)
A coil is the component that will generate as high a voltage as it needs to, in an attempt to sustain current flow when resistance suddenly goes high. It may even produce a spark, the voltage can get that high.
So mathematically speaking the coil might be said to generate near-infinite voltage.
If you want a current source that gives you high voltage you should check out boost converters. They utilize a coil to work as a current source, that can raise voltage to high values (limited by the insulator thickness etc for discharge and leakage currents on coil and other PCB elements). That would mean that ideal components would raise the voltage to infinity.
Infinite voltage has not yet been achieved though, but good luck in trying
Hello
i has read "http://en.wikipedia.org/wiki/Buck_converter" article but it shows me that the Energy from inductor transfer to Capacitor.but i want to know how can we charge a capacitor with a Current source.
Any help appreciate
as you know if create a Current source with transistor and put the capacitor as load it only charge until Vc=VEE,doesn't take more voltage.
i want to demonstrate the capacitor integral voltage the increase with Current
as you know if create a Current source with transistor and put the capacitor as load it only charge until Vc=VEE,doesn't take more voltage.
i want to demonstrate the capacitor integral voltage the increase with Current
Yes, that happens because no current source (or anything else) is a perfect. You may build a "perfect integrator" (that is what you want) in a limited domain.
The op-amp at your right is a perfect integrator... until the output clips! It will integrate the voltage that the left op-amp outputs. The whole circuit is a simple oscillator: the op-amp at the left is configured as a schmitt-trigger and outputs a square wave. The right op-amp is the perfect integrator: it will integrate a positive voltage as an ascending ramp and a negative voltage as a descending ramp. The schmitt-trigger toggles depending upon the voltage of the perfect integrator, assuring this last one is always working on its domain.
Dear baby_1
Hi again
can you tell me that what do you want to do , exactly ? perhaps there are better ways ( better than charging a capacitor !!!!) available . if you tell us a bit more about the aim of this project perhaps we can help you as well as possible . unless it is a hobby . and not for any specific aim ?
Best Luck
Goldsmith