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??? Index exceeds matrix dimensions. ERROR

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fardeen

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hi there,
I have encountered the problem of matrix dimension, can anyone help? Here is the code
additional info: indexgood = 1
for j = 1:indexgood-1
errors = realerrors;
eval(['[mse1:),j),mse2:),j),qlike:),j),r2log:),j),mad2:),j),mad1:),j),hmse:),j)] = lossfunctions(errors,V',num2str(j),',1,T+1,invT);']);
eval(['numpar(j) = size(param',num2str(j),',1);']);
eval(['logl(j)=L',num2str(j),';']);
eval(['aic(j) = (-2*logl(j) + 2*numpar(j))/T;']); % Formulas from eviews' maunual
eval(['bic(j) = (-2*logl(j) + numpar(j)*log(T))/T;']);
end

temp = [mse1:)),mse2:)),qlike:)),r2log:)),mad2:)),mad1:)),hmse:))];
lossfun = [temp(5:3:11,:); temp(6:3:12,:); temp(7:3:13,:); temp(1:4,:)];
temp2 = [numpar' persistence' aic' bic' logl'];
others = [temp2(5:3:11,:); temp2(6:3:12,:); temp2(7:3:13,:); temp2(1:4,:)];

??? Index exceeds matrix dimensions.

Error in
lossfun = [temp(5:3:11,:); temp(6:3:12,:); temp(7:3:13,:); temp(1:4,:)];


Thank you

- - - Updated - - -
 
Last edited:

It will be much easier to help You, when You tell us what is the size of temp matrix.
Just put the breakpoint at line with
lossfun = [temp(5:3:11,:); temp(6:3:12,:); temp(7:3:13,:); temp(1:4,:)];
and read the size from workspace.
 

It will be much easier to help You, when You tell us what is the size of temp matrix.
Just put the breakpoint at line with
lossfun = [temp(5:3:11,:); temp(6:3:12,:); temp(7:3:13,:); temp(1:4,:)];
and read the size from workspace.

Thank you very much for reply
I have checked and it shows 9x7 double. While each of component: mse, mse2.... are 1x9 double
thank you
 

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