In my opinion, the switching style will affect the electrical dynamic of the dc motor. For example, during the OFF state of Hard-Switching PWM (S1, S2, S3, S4 are OFF), the Vs term is included in the model equation (Blue line). On the other hand, during the OFF stage of Soft-Switching PWM (S4 is ON, other are OFF), the Vs term is NOT included in the model equation (Green line).bittware said:I agree. However, regardless of what switching style is, I think the phenomenas are the same.
Let me tries to describe:bittware said:Maybe I should simplify my question in a general manner.
First, I know how to calculate the current variation in a stationary inductor under a varying driving voltage source such as PWM controlled voltage source.
Second, I don't know how to calculate the current variation in a mobile inductor which is not only controlled by varying driving voltage, but also affected by surrounding magnetic because of its motion.
I think simply sum up the current caused by these two sources is not correct, but I can't find right solution. So here I am to ask for your help.
Good catch ! :wink:bittware said:Expect equation(3) and (4) seem to be not equivalent.
Another definition of soft-switching:bittware said:To be honest, I haven't heard of Hard-switching and Soft-switching concept before.
From your description, I conclude Hard-switching means current "fast-decay" and Soft-switching means current "slow-decay". Am I right?
What are the characteristics of these two switching sytles?How to apply them properly?
P.S. Could you provide some reference which introduce the concept of Hard-switching and Soft-switching?
The magnitude of Vemf does not rely on the armature current. It depends on current in 'field winding'. However, in your case, the field winding has been replaced by permanent magnet already. So, Vemf is just dependent of the motor speed.bittware said:.... I can't figure out the Vemf=K*w(t) in explicit form because I(t) is no more constant with repect to parameter t. .... If I should regard w(t) as constant during PWM off state for simplification?
Hello nicleo,nicleo said:So, Vemf is just dependent of the motor speed.
Hello usernam,usernam said:However if you have a power that is directly proportional to say torque then motor speed is constant.
bittware said:I am using PWM to control DMOS H-bridge to drive a brush DC motor. When PWM switches off, the current flowing through inductor can't be cut simultaneously. It will find a path through freewheeling diode. But the motor rotor is still spinning, the Back-EMF has a trend to force the current to inverse.
My question is:
Whether the current flowing through motor inductor would reverse or wouldn't reverse at all in a limited switch off time?
nicleo said:When switch is OFF, the current flowing through inductor could not reduce to ZERO instantaneously. The direction of the current flow will not reverse.
bittware said:Assuming a extreme condition, if a rotor has been accelerated to a relative high speed and the driving power withdraws, the rotor will act as a generator. The kinetic energy will be converted into electric energy, meanwhile the current is reversed. How to explain this case?
nicleo said:No. The current will still in the same direction, i.e. not reversed. I assume that in your case, there is no 'external' torque to drive the motor (rotor) after the driving power is removed. The current flows through the motor winding, after the driving power is removed, will not change or reverse direction.
bittware said:Althogh after driving power is removed no external torque drives the motor, the residual kinetic energy instored in rotor itself will also be converted into electric energy. Right? So I believe a part of kinetic energy will cause revesed current eventually. What I am concerning is when the reversed current appears after the PWM switches off.
nicleo said:When Stage 2 (i.e. swtiches (S1, S2, S3, and S4) are OFF, just after motoring current decays to ZERO, and rotor still rotates), and if the stator has permanent magnet or the residual magnetic field on stator is strong enough:
Current path: -PS -> D4 -> motor winding -> D1 -> +PS
In this case, both the current at PS terminals and in motor winding are reversed (based on Fleming's rules) because the rotor is still in 'clockwise' direction.
username said:bittware are you refering to some sort of regeneration. If you are then yes eventually the current in the inductor will reverse. But not instantaneously. It will first decay to zero and if you are still in regenerative mode the current will go negative. Ofcourse you have to provide a path for the reverse current so you must be using a Hbridge or a Class C chopper.
username said:Now suppose inductor current has finally come to zero while motor is still rotating in the same direction. We turn S2 on and S1 and S4 off. Voltage across the inductor becomes negative (using previous refernce directions) so current through the inductor falls i.e it becomes negative. Current flow is D4 Dc motor and then S2 then back to D4. Now regenerative process has begun. Now we are using the Hbridge in boost converter mode. Now turn S2 off and D1 begins conducting. Voltage across the inductor is positive so the inductor current rises i.e becomes less negative. Current flow is D4 then DC motor then D1 then source and back to D4. So now the average inductor current is negative. Average power flow is from motor (now a generator) to the source.
bittware said:What I care about is the current variation in inductor when PWM swithes off. Based on common sense, the motor resistor will consume up the energy stored in indutor during recirculation phase. And as for PWM off time is enough long, the current will alternate its direction finally. Bigger the motor resister is, quicker the current changes its flowing direction.
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