Dec 17, 2017 #1 N noisepic Member level 3 Joined Nov 2, 2012 Messages 66 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,286 Activity points 1,781 I have a bridgre rectifier curcuit able run at 25A. The input is AC 30V, the measure output power is easy P=Vdc*Idc. But input measure by VAc*Iac rms at low current make eff > 100%. Is the problem of power factor?
I have a bridgre rectifier curcuit able run at 25A. The input is AC 30V, the measure output power is easy P=Vdc*Idc. But input measure by VAc*Iac rms at low current make eff > 100%. Is the problem of power factor?
Dec 17, 2017 #2 H Hendribs153 Newbie level 5 Joined Dec 16, 2017 Messages 8 Helped 0 Reputation 0 Reaction score 0 Trophy points 1 Activity points 45 How is it possble eff > 100% ?. Calculate eff by (Pout/Pin)*100%
Dec 17, 2017 #3 KlausST Advanced Member level 7 Joined Apr 17, 2014 Messages 25,292 Helped 4,874 Reputation 9,769 Reaction score 5,570 Trophy points 1,393 Activity points 169,364 Hi, You need a true AC power meter. A good one, because cheap one probably show alot if error when current waveform isn't sine shape. VAc*Iac rms Click to expand... P = V_RMS x I_ RMS x powerfactor Where powerfactor = cos(phi) for sinusoidal waveform only. Klaus
Hi, You need a true AC power meter. A good one, because cheap one probably show alot if error when current waveform isn't sine shape. VAc*Iac rms Click to expand... P = V_RMS x I_ RMS x powerfactor Where powerfactor = cos(phi) for sinusoidal waveform only. Klaus