How to design X-Band 1:2 Microstip T-junction power divider in ADS

[Manoj_N]

I wanted to design an X-Band 1:2 Microstrip T-junction power divider using ADS but I couldn't achieve the desired condition that is S(2,1) = S(3,1) = 0. Can someone help to solve this problem?

 

[psach27]

Hi!

Why do you need that condition? What is your input? port 1?
Regards

 

[volker@muehlhaus]

I couldn't achieve the desired condition that is S(2,1) = S(3,1) = 0.

This is not possible with a passive divider. Best case for a lossless divider is S21=S31=-3dB

 

[Manoj_N]

Hi!

Why do you need that condition? What is your input? port 1?
Regards

My return loss should be less -30dB for optimum performance. Same for port 2 and 3

 

[Manoj_N]

This is not possible with a passive divider. Best case for a lossless divider is S21=S31=-3dB

how to is -3dB? Is there a way to calculate it?

 

[Manoj_N]

Hi!

Why do you need that condition? What is your input? port 1?
Regards

Check the attachment. I designed the schematic.

 

[volker@muehlhaus]

how to is -3dB? Is there a way to calculate it?

This is simple: in an ideal lossless case, each output gets half the power (-3dB).

Regarding your design: have a look at Wilkinson divider basics.

 

[biff44]

Check the attachment. I designed the schematic.
View attachment 185964

in a couple such as this, adding a 100 ohm chip resitor across the two outputs near the end of the two quarter wave lines WILL make it behave happier in your circuit. that is because if there are different load conditions for the two outputs, the resistor will absorb some of that mismatch power.