How to calculate poles and zeros if the slope is less than 20db/dec?

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el120

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how to find the poles and zeros if the roll off is less than 20db/dec?
i know if it is 40db/dec there are two poles or zeros but i have no clue for 10db/dec. is it going to be half? but how?
 

Re: how to calculate poles and zeros if the slope is less than 20db/dec?

I guess it's a theoretical question with no reference to a real circuit.

There's no elementary circuit with 10 dB/decade slope. A respective frequency characteristic can be only approximated by a combination of multiple poles and zeros.
 

Re: how to calculate poles and zeros if the slope is less than 20db/dec?

yes it is a theoretical subject and is give by my instructor. i have no clue ho to solve it :s
 

Re: how to calculate poles and zeros if the slope is less than 20db/dec?

el120 said:
i have no clue for 10db/dec.
Click to expand...

Perhaps the y-axis means power, not voltage?
 

Re: how to calculate poles and zeros if the slope is less than 20db/dec?

I did not read this, it was just a quick search.
**broken link removed**
 
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Re: how to calculate poles and zeros if the slope is less than 20db/dec?

i also thought. but no this aint power
 

Re: how to calculate poles and zeros if the slope is less than 20db/dec?

As, said the -10 dB/decade can be only implemented as an approximation, usually with equal ripple error. A typical example is a pink noise filter, implemented as a R-RC ladder circuit. See as example **broken link removed**

For an actual design, specify ripple and frequency range.
 
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    CataM

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el120 said:
View attachment 142628

how to find the poles and zeros if the roll off is less than 20db/dec?
i know if it is 40db/dec there are two poles or zeros but i have no clue for 10db/dec. is it going to be half? but how?
Click to expand...

Hi,
There is change of +10 dB/decade to -10 dB/decade. so total change is -20 db per decade.
So, there will be one pole .

-40dB/decade has two poles.
+40dB/decade has two zeros.


For less than 20dB/decade, there would be constant term(not sure).

Thanks
 

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