Johnny_YU
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The circuit has different low-pass cut off frequencies for common and differntial mode signals. Preferably you draw equivalent circuits for both operation modes and calculate it.
Common mode filter 1 is correct.
For the differential mode, the first circuit is roughly correct, but the 1MOhm and 100 pF must be considered for exact transfer function. What you name "common mode filter 2" is acually the exact single ended equivalent circuit of the differential mode filter.