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Hi Am a newbie trying to understand how switch mode regulators work.
Say I wanted to convert 32v into 12v using a linear reg @1A then I would dissipate extremely large amount of heat.
But I always been told if you use a buck converter instead you dissipate less heat. On this website https://mike-thomson.com/blog/?p=246
Mike explains that when the the pass transistor inside the reg switches off, the ouput cap will eventually be discharged via the switching diode until
the transistor is switched on again.
My understanding:
Am I correct in saying it gives off less heat because unlike a linear regulator it doesn't drop 20v@output current
across the regulator. Instead it uses the supply voltage to trickle charge the capacitor to the desired voltage. So as long as the regulator switches off it's
pass transistor in time it'll be only be partially charged to the desired voltage. When the transistor is switched off the capacitor is discharged via the diode.
The regulator switches the pass transistor on to charge it back up. This happens at such a high frequency, the load receives a relatively stable output voltage.
Say I wanted to convert 32v into 12v using a linear reg @1A then I would dissipate extremely large amount of heat.
But I always been told if you use a buck converter instead you dissipate less heat. On this website https://mike-thomson.com/blog/?p=246
Mike explains that when the the pass transistor inside the reg switches off, the ouput cap will eventually be discharged via the switching diode until
the transistor is switched on again.
My understanding:
Am I correct in saying it gives off less heat because unlike a linear regulator it doesn't drop 20v@output current
across the regulator. Instead it uses the supply voltage to trickle charge the capacitor to the desired voltage. So as long as the regulator switches off it's
pass transistor in time it'll be only be partially charged to the desired voltage. When the transistor is switched off the capacitor is discharged via the diode.
The regulator switches the pass transistor on to charge it back up. This happens at such a high frequency, the load receives a relatively stable output voltage.