capacitor cutoff
thank you for the fast reply..
yes.. i have read the malvino - electronic principles but it's translated into my language, not the english version, i don't have the english version, i can't understand what the translater say in my book, there are a lot of strange words and it's impede me to understand about it ..
sorry, where is the file?? and from what i read in the book is, for determine the high and low cut off frequency, we should analyze from Cin, Cout, CE, Cc' and also Cstray, right? for the determine the cut off frequency,Xc should be = R, where R = Zin+Rs, Zin = R1//R2//βr'e, and Rs is the series resistance from the input voltage, Xc = 1/2pifCin, so fin = 1/(2pi(Zin+Rs)Cin), is it right? and for the output frequency (Xc=R), Xc = 1/2pifC, R=Zout, Zout = Rc? C = Cc' + Cstray, so, the fout = 1/(2piZoutC), and i am confused about the bypass capacitor, it said that Ce parallel with emitter resistance, so when Xc = R, R = r'e+(R1//R2//Rs)/β, and therefore f = 1/(2piRCe) <- what frequency is it?
and from these three frequency, which one is high cut off frequency? and which is the low cut off frequency??
please give me a brief explanation..
thank you very much..
Added after 13 minutes:
okay.. sorry.. i've seen the attached file now.. i will try to read it at home.. and will ask again if there are something i don't understand from the attached file..
thank you very much..