Oct 10, 2004 #1 D david90 Advanced Member level 1 Joined May 5, 2004 Messages 423 Helped 9 Reputation 18 Reaction score 4 Trophy points 1,298 Activity points 3,611 Sinusodial RL anaylysis I have Source = 20cos(800+25), Resistor = 80, L=75mh and they are all connected in series. Find the current I(t) My teacher wrote out 20cos(800+25)= 80I+75mh(di/dt). Then I he used euler's ident to convert 20cos(800+25) to 20e^(j25). so 20e^(j25)= 80I+75mh(di/dt) after i'm kinda lost on what to do. Can somebody help me finish it by using the method above?
Sinusodial RL anaylysis I have Source = 20cos(800+25), Resistor = 80, L=75mh and they are all connected in series. Find the current I(t) My teacher wrote out 20cos(800+25)= 80I+75mh(di/dt). Then I he used euler's ident to convert 20cos(800+25) to 20e^(j25). so 20e^(j25)= 80I+75mh(di/dt) after i'm kinda lost on what to do. Can somebody help me finish it by using the method above?