julian403
Full Member level 5
I have to do a correction circuit bit7, using hamming. I did the next:
![WP_20150413_005.jpg WP_20150413_005.jpg](https://www.edaboard.com/data/attachments/52/52251-f85a8b2f000289880b3ca5d2246ce5f0.jpg)
As you can see, there is 4 bits, so there must to be 3 redundant bits. I did the 3 C and the parity bits are b1 , b2 and b4.
But, how the receiver circuit can correct the bit 7?, after the transmittance in the receiver
I think b7 is:
b7= b4 x b5x b6x or b7= b2xb3xb6 or b7=b1xb3xb5
where x is xor gates.
or maybe I must use the Cs bits to correct the 7 bit ?
![WP_20150413_005.jpg WP_20150413_005.jpg](https://www.edaboard.com/data/attachments/52/52251-f85a8b2f000289880b3ca5d2246ce5f0.jpg)
As you can see, there is 4 bits, so there must to be 3 redundant bits. I did the 3 C and the parity bits are b1 , b2 and b4.
But, how the receiver circuit can correct the bit 7?, after the transmittance in the receiver
I think b7 is:
b7= b4 x b5x b6x or b7= b2xb3xb6 or b7=b1xb3xb5
where x is xor gates.
or maybe I must use the Cs bits to correct the 7 bit ?
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