garvind25
Full Member level 3
Hi,
I was trying to make a LVDS driver. In this connection, I am referring to the paper here. I am unable to understand how VCM voltage is getting generated. I hope someone can help me.
As per the LVDS standards, the nominal current through switching bridge is 3.5 mA (Iout). The LVDS standards also require a VCM (nominally of 1.25v) to be generated by the driver. As per the paper,to generate this Vcm, the circuit uses two 10K resistors as voltage divider. But as per my calculation, (pls. see the image below), the Vcm is coming out to be 0.174v [(3.5mA X ((10k+10k)||100))/2].
Where am I going wrong/ what am I missing here. Any guidance is welcome.
Looking forward to your replies.
Thanks and Regards,
Arvind Gupta.
I was trying to make a LVDS driver. In this connection, I am referring to the paper here. I am unable to understand how VCM voltage is getting generated. I hope someone can help me.
As per the LVDS standards, the nominal current through switching bridge is 3.5 mA (Iout). The LVDS standards also require a VCM (nominally of 1.25v) to be generated by the driver. As per the paper,to generate this Vcm, the circuit uses two 10K resistors as voltage divider. But as per my calculation, (pls. see the image below), the Vcm is coming out to be 0.174v [(3.5mA X ((10k+10k)||100))/2].
Where am I going wrong/ what am I missing here. Any guidance is welcome.
Looking forward to your replies.
Thanks and Regards,
Arvind Gupta.