Generation of N bit random bit stream in verilog

envyh123 · Mar 25, 2015

I dont want to generate it using LFSR, i want to use $random function of verilog to generate a random 8 bit data stream. I have generated random integer from 0 to 255 using the following code.
Can anyone suggest methods to convert this into 8 bits
My code :

Code Verilog - [expand]
1
2
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9
initial
begin
integer num;
repeat(100) @(posedge clock)
begin
#2;
num<=$urandom_range(255,0);
end
end

dipin · Mar 25, 2015

hi,

" $urandom " system verilog not verilog.

.you can put something like this

value <= num[7:0];
so first 8 bits will be stored into value.

regards

dave_59 · Mar 25, 2015

Did you mean to ask how to serialize an 8-bit value into a stream of 1-bit values?

Code:

bit signal;

initial repeat (100)
           begin
             bit [0:7] num;
             num = $urandom;
             for(int i=0;i<8;i++)
              @(posedge clock)
                 signal <= num[i];
           end

Generation of N bit random bit stream in verilog

envyh123

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dipin

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dave_59

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envyh123

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Code Verilog - [expand]
1 2 3 4 5 6 7 8 9	initial begin integer num; repeat(100) @(posedge clock) begin #2; num<=$urandom_range(255,0); end end

Generation of N bit random bit stream in verilog

envyh123

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dipin

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