Generation of N bit random bit stream in verilog

[envyh123]

I dont want to generate it using LFSR, i want to use $random function of verilog to generate a random 8 bit data stream. I have generated random integer from 0 to 255 using the following code.
Can anyone suggest methods to convert this into 8 bits
My code :

---

Code Verilog - [expand]
1
2
3
4
5
6
7
8
9
initial
begin
integer num;
repeat(100) @(posedge clock)
begin
#2;
num<=$urandom_range(255,0);
end
end

---

 

[dipin]

hi,

" $urandom " system verilog not verilog.

.you can put something like this

value <= num[7:0];
so first 8 bits will be stored into value.

regards

 

[dave_59]

Did you mean to ask how to serialize an 8-bit value into a stream of 1-bit values?

bit signal;

initial repeat (100)
           begin
             bit [0:7] num;
             num = $urandom;
             for(int i=0;i<8;i++)
              @(posedge clock)
                 signal <= num[i];
           end