format specifier problem in c-language

[v.s.n.kumar]

Hi,
can anybody tell what is the result of below lines in c.
main()
{
int i=0x90;
printf("%%d",i);
}

 

[ahmad1954]

if you use 2 % in printf in output you have %d. so your output is %d. but if use printf("%d",i) output is 144 decimal of 90 hex.

 

[v.s.n.kumar]

I know that the result is %d. but what is the reason for giving as %d

 

[ahmad1954]

you should use one %. because % is for formatting and every time that compiler see %,it looks for formatting option, for example d or f. and if you want to print % character, you should use %%.