explanation needed in a power supply

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Looking at the positive circuit, as output current increases, the voltage drop across the emitter resistors(r10/r14) increases, t3 will conduct more, causing t4 to conduct less and therefore causing t5/t6 to conduct less.
 

The voltage drop is senses over the emitter resistors of the power output transistors. This will turn on T3/7, which will turn on the opto's to remove the drive from T4/8 to limit the current to output transistors.

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It looked like me and barry replied at the same time.
 


Great minds think alike.
 

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