Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

dq transformation using PSIM

Status
Not open for further replies.

almotions

Newbie level 4
Joined
Jun 16, 2007
Messages
6
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
1,323
dq transformation

Hi,
recently,i'm doing some experiment to convert from 3 phase balanced input to dq components to calculate the active power.



i've also attached the simulation results:


As you can see,i've included the wattmeter to measure the active power drawn by the load(R=20 ohms) which shows 605Watts at steady state. But when i use the dq transformation and calculate the active power based on the formula P=VdId +VqIq
which is shown on the first graph,P=V23*V21+V24*V22 ,it gives a value of 400W at steady state.Is there anything wrong with my assumptions or diagram?

Another question. for dq transformation, why the direct and quadrature component remain at a constant value despite of change in theta with time (theta=wt)

Please help.Thanks lots
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top