noiseless
Full Member level 3
I tried to use single stage OTA to realize differential to single conversion. The block diagram is shown in Fig. 1 and the OTA schematic is shown in Fig. 2.
The Vo relates to the input signal is as
Vo = Vinp – Vinn
In order the input impedance is the same, C2 is chosed to be 2*C1. However, I found the s11 (Fig. 3) is still different and the Vinp is still 2 dB higher than Vinn. The circuit is operated at 2.5GHz.
What is the reason?
The Vo relates to the input signal is as
Vo = Vinp – Vinn
In order the input impedance is the same, C2 is chosed to be 2*C1. However, I found the s11 (Fig. 3) is still different and the Vinp is still 2 dB higher than Vinn. The circuit is operated at 2.5GHz.
What is the reason?
