Maverickmax
Advanced Member level 1
differential input instrumentation amplifier
Hi
I understand the principle behind the differential input amplifier equation such as
R2a/R1a=R2b/R1b
Vout/V1-V2=R2/R1
What really confuse me is why a pull-up resistor is connected to the non-inverting. Can anyone kindly please explain the reason of using the pull-up resistor.
Is it kind of a potential divider? If yes, why then?
Regards
Maverickmax
Hi
I understand the principle behind the differential input amplifier equation such as
R2a/R1a=R2b/R1b
Vout/V1-V2=R2/R1
What really confuse me is why a pull-up resistor is connected to the non-inverting. Can anyone kindly please explain the reason of using the pull-up resistor.
Is it kind of a potential divider? If yes, why then?
Regards
Maverickmax