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Differential Input (Instrumentation) amplifier

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Maverickmax

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differential input instrumentation amplifier

Hi

I understand the principle behind the differential input amplifier equation such as

R2a/R1a=R2b/R1b

Vout/V1-V2=R2/R1

What really confuse me is why a pull-up resistor is connected to the non-inverting. Can anyone kindly please explain the reason of using the pull-up resistor.

Is it kind of a potential divider? If yes, why then?

Regards

Maverickmax
 

ptmsl

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There is no pullup neccesary at the differential amplifier except if your design is powered from a single supply voltage. Can you give me your schematic?
 

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