To analyze differential behaviour, you distinguish between common mode and differential input signals to simplify the calculation. The circuit shows a differential signal. Real operation usually involves both kinds of signals superimposed.
To analyze differential behaviour, you distinguish between common mode and differential input signals to simplify the calculation. The circuit shows a differential signal. Real operation usually involves both kinds of signals superimposed.
perhaps the following explanation can help to understand FvM`s reply:
*Assume any two different input voltages Vx and Vy (same sign or not) ,
* You always can split these voltages in two new parts Vcm=(Vx+Vy)/2 and Vd/2=(Vx-Vy)/2 ,
* By superimposing both parts you will get again Vx and Vy: Vx=Vcm+Vd/2 and Vy=Vcm-Vd/2 ,
* Now you can amplify (separat for common mode and diff. signals) with the respective gain values Gcm and Gd:
Common mode Vcm*Gcm=Vout,cm
Diff. mode Vd*Gd=Vout,d
* Then, both output voltages are added (normally, the common mode signal is very small).
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This procedure shows that there is a common mode voltage also for the case Vx=0 (or Vy=0).