DFT Visualizer Data View

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Vignesh_J

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Hi I am trying to debug a simulation mismatch. I am viewing the design through DFT Visualizer. I gave the pattern index of the simulated pattern. The visualizer shows 9 bits of data for each pin in the instance. It is something like this.

Code: 
D 000-000-000 Q 000-100-000-[0]


What does it mean?
 


It means your FF.Q expected value 0 after unload (shift out the data to the scan chain) .
I can explain more about it :
Q 000 - 100 - 000
[shift in ] - [capture ] - [shift out]

Tiep Ngo
 

It means your FF.Q expected value 0 after unload (shift out the data to the scan chain) .
I can explain more about it :
Q 000 - 100 - 000
[shift in ] - [capture ] - [shift out]
Click to expand...

I see three shift pulse when SE in enabled. So Shift in data of Q 000 means that three 1'b0 are shifted in the scan chain at shift clk right?
Correct me if I am wrong.
 

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