The first 'void' informs the compiler that this function returns nothing.
The second 'void' informs the compiler that this function takes no arguments.
Function return type: 'void' no return type
Function name: '__divsi3'
Function arguments: '(void)' no arguments.
The Braces would normally contain the code that implements the function.
void __divsi3(void)
{
c code to implement function
}
In this case, they contain nothing, so the function does nothing.
The comment
/* Instruction emulation. */
is written by the programmer, normally to make clear what the function does.
So this is meaningless. You could put any old gibberish here, it is ignored by the compiler.
This comment suggests that the function will emulate an assembler instruction, maybe some type of divide routine?
So, to sum up, it does nothing and is meaningless.
If you havnt already done so, get a book on
The C programming language.