prawesh2000
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Yes , it means peak to peak ripple voltage .1. What is the 'vrpp'? Is it the voltage ripple?
It is simple ! both are the same ! if you use two mosfet ( h side , and l side ) that both of them are nmosfet , for lside you won't have any problem but for h side mosfet , you'll have problem ! you can connect the ground of control signal ( PWM ) to the minus supply but you can't connect it to the source of h side mosfet . so we have to use a method that called bootstrap ( it isn't the way that you probably hear at class A amplifier ! , it is completely different ) . so , here in this project you haven't minus supply , but if you want to drive your hside mosfet , that bootstrap capacitor , can't be full of charge , because it hasn't any loop , to the ground ! so , if you use another mosfet instead of diode at buck regulator , usually , they have a diode , internally , that called anti parallel diode . this diode will do duty of that famous diode at buck configuration , and this mosfet will provide a path to the ground , thus , your bootstrap capacitor can be full of charge . this capacitor will connect to the GS junction of your mosfet automatically , and thus your mosfet can be turn on / turn off , easily .2. I have not been told about the bootstrap driver by my professor. But, yes, he told that we are going to use a gate driver. Are they same?
It isn't important to find ton and toff ! do you know why ? because if you have PWM for your series switch , the command signal of another mosfet will be PWM' . but not , pwm' , exactly . you'll need to create enough dead time , with a simple shmitt trigger not gate and an RCD network to prevent overlap problem .3. I have to use two switches. So, I have to find the Ton and Toff for both of the switches. How can I do that?
For efficiency , calculations , of a simple buck converter , we can use a simple approximation ( according to the pressman's book ) that loss power , is equal to the value of current ! so we can say efficiency = pout/(pout+ploss+prect)4. How can I find the total power loss in the circuit? They said that the converter should give >85% efficiency.
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