Re: 4x4 multiplier in vhdl
Hello
1- No one is going to "draw" the code for you.
2- concerning the 4 leds problem, for any multiplier it is very common to just neglect half of the bits(or less) in the result register.
For example 1011)binary * 0010)binary which is 11x2 in decimal the exact result should be 00010110, now we can either throw the most 4-bits or the least 4-bits depending on your needs, i.e which part is more important for your computations.
3- To write a code for 4x4 multiplier, the easiset way is called "Add and Shift", google for it and you'll get your answer.
Best Wishes,
Sameh Yassin