..piece by piece information.Unfortunately the controller cant control the delay because the outputs are used up.
Crutschow, is it possible that this circuit will also act as a soft start?
We don't knowPlease draw as sketch with voltages and timing.
Not readily.it possible that this circuit will also act as a soft start?
I agree that -especially for capacitive loads - there is a benefit in limited voltage rise rate. Anything about 1...10V/ms.
Extremely slow rise rate is a quite untypical requirement for a power supply or a device.
Add 1mF to each output and show temp rise on FETsBelow is the LTspice simulation of my circuit with a soft-start function added, and MOSFET outputs to provide the 3A maximum current.
C1 and C2 generate a MIller effect integrator function to give about a 1 second linear ramp of the output voltages.
I think with that you likely don't also need a delay.
The diodes and resistors R7 and R8 are to help discharge the capacitors and reduce the turn-off time to be similar to the turn-on time.
The N and P MOSFETs can be just about any with at least a 30V rating, and an on-resistance ≤50mΩ.
The should also have similar Vgs(th) values.
View attachment 172746
Why 1mF?Add 1mF to each output and show temp rise on FETs
I was later think about a motor with 0.75 DCR and then simulated it with 12W peak power for a 5s ramp with a suitable friction coefficient and torque to load with 2A. Yes C is irrelevant .Why 1mF?
The energy dissipated in the MOSFETs from charging a 1mF capacitor to 15V is 1/2 CV² or 112mJ, which will not cause a noticeable amount of heating.
The device is not a standard motor, it's a scanner.I was later think about a motor with 0.75 DCR
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