Dont you require a ground for your sensor ?
Hi,
I assume you know Ohm´s law.
Now if I use your informations. 20mA.. and a 10k in series... this means 200V across the resistor.
--> there´s something wrong with your data.
***
You need a circuit to transform the sensor current into a measurable voltage.
--> the simplest circuit is to use the one that you show in your post.
The simple math you can do on your own.
Klaus
Your answer doesn't relate to my post.i'm getting milliamps reading as negative value...
By this way how to do it..?
Why did you change the circuit now? It just makes things more difficult.--> the simplest circuit is to use the one that you show in your post.
Hi,
Why did you change the circuit now? It just makes things more difficult.
Klaus
Hi,
You gave the circuit in post#1
I told you it´s the simplest solution.
Now you searched for other circuits.
Therefore I have to assume you don´t like a simple solution.
How difficult do you want it`?
Klaus
Hi,
I really don´t know what you want to hear.
In my eyes: The first circuit is the solution. Just calculate the correct resistor value. Simply using Ohm´s law. That´s it.
I think I already told you this in post#3.
Klaus
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