Converting binary held in two 8 bit registers to bcd 3 digit (0 to 999)

[rolg]

a newby needs help--using 16f874a , assembly . i am having trouble converting binary held in two 8 bit registers to bcd 3digit (0 to 999). help !
thanks more than i can say

 

[bungee-]

pic bcd 8 bit

http://www.piclist.com/techref/microchip/math/radix/b2bhp-8b3d.htm

Try this, or browse code on same site.

 

[rolg]

Re: 8 bit to bcd 3 dig

THANKS SO MUCH FOR HELP.. i looked but found no routine that handled 0 to 999. just 0 to 256 -which needs only one register.

 

[chrismicro]

Re: 8 bit to bcd 3 dig

If it was PIC Basic then its easy you put your binary number in a word variable and use the DIG command to read one digit of the 16 bit number up to 5 digits 65535 Basic is so easy the compiler do all the hard work for you and if you still want to do assembler you can incorporate your ASM code in PIC Basic