for reactive is cos(phi) or for active??Power (watts) = V*I*pf.
for reactive loads, you are correct, power factor it is cos(phi).
for electronic loads, it is related to harmonic distortion: pf = 1/sqrt(1 + THD^2)
for reactive is cos(phi) or for active??
then for LED lamps or fluorscent we can type the formula for calculation the power as : P=VI(1/sqrt(1+THD^2) ??
1-now LED lamps are reactive or active? (is reactive equal to non-linear and active equal to linear or no? )reactive is the phi angle
active is the THD value.
Unfortunately, you won't be able to measure neither without a power analyzer. Which will also provide a watt reading directly, you don't need to calculate anything.
It does use voltage and current, but also their relation. As said, by multiplying instantaneous voltage and current values. A classical electricity meter determines real power respectively energy (it's integral) by electromechanical means as explained here https://en.wikipedia.org/wiki/Electricity_meter#Electromechanical_metershow this equipment measure the power? don't use voltage and current?
A T8 retrofit LED tube as shown in the photo will be operated with the standard choke ballast
I read in a catalog from manufacturer that this type of lamp (LED t8) has driver and dont need ballast (choke) and starterIs it really true? Do they also need a starter?
A conventional fluorescent tube is a gas discharge tube that needs a relatively high striking voltage and a constant current (limited) afterwards. As run from a AC source, the tube goes off twice every cycle.
I was talking about retrofit LED tubes. There are different types to be used in existing lamps either with electromagnetic or electronic ballasts. The types designed for electromagnetic ballast may even use a special "starter" replacement device, of course not a real starter.Is it really true? Do they also need a starter?
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