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I have designed a class-E switching power amplifier with 3.3v DC supply to deliver 1W power through 50ohm resistor and got some output in cadence which I have attached here.
Please help me to understand the output for the circuit.
Because you are trying to get 2W from a 3V supply, you get 6Vpeak at the collector ~ 2V RMS, so 2^2/R = 2, R = 2, so the collector impedance at the collector is 2 ohms this must be matched to the aerial (50 ohm). This is done with the PI network. The series L1 is larger then necessary due to C3 in series, so it acts like the required value at 50 MHZ. At 500 MHZ it acts like a big L, so the resonant frequency is between 50 and 500. The increased reactance of L1 rejects more of the 500 MHZ getting to the aerial.
Frank
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