gmeir11
Newbie level 1
Hi all...
This is kinda theoretical question about how cascode current mirror works.
I've serached it all over the web and haven't found the answer.
The diode connection sets: Vgs1 = Vgs3 = Vds1 = Vds3
(given that all the transistors are the same).
After solving the nMos current equation, with taking in consideration the channel length modulation by (1+λVds)
I got Vgs1 = Vgs3 = Vds1 = Vds3 = Vgs2 = 2V
How can I now determine the current in the right branch (through N2, N4) ?
I've read that I can assume the voltage over N2 is constant. Why is that? and how does that assist me?
Thank !!! 8-O
This is kinda theoretical question about how cascode current mirror works.
I've serached it all over the web and haven't found the answer.
The diode connection sets: Vgs1 = Vgs3 = Vds1 = Vds3
(given that all the transistors are the same).
After solving the nMos current equation, with taking in consideration the channel length modulation by (1+λVds)
I got Vgs1 = Vgs3 = Vds1 = Vds3 = Vgs2 = 2V
How can I now determine the current in the right branch (through N2, N4) ?
I've read that I can assume the voltage over N2 is constant. Why is that? and how does that assist me?
Thank !!! 8-O