can any explain me this circuit

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praveen_palaparthi

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hi friends can anyone explains this circuit how the mosfet is turned off when over loaded
 

Where is the out put?
May be this:
When the current of last R increases turn the diode on and the current of MOS decrease to Zero...
 

Output is connected to primary of the transformer.The circuit shown is only one leg actually full circuit is a PUSH PULL inverter which consists of same circut connected to other end of transformer.

The last resistor is snubber its is in complete leave it.
I want to know is when the 5th(left to right)transistor is turned on.If that transistor is turned on there will be no pulse to MOSFET so mosfet is turned off.

This is circuit is for overload detector if output is overloaded the MOSFET has to switch off. How to switch off the mosfet the only way is,to turn on the transistor(5th one).How????
 

Please send complete circuit and say where the overload happen? (which transistor!!)
 

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